08-01-2017, 13:01
Kako se izračuna energija izstrelka? Za IPSC faktor vem: masa krogle v grains x hitrost v feet/sec deljeno s 1000. Kako pa se izračuna energija v Joulih, bi bil zelo hvaležen za razlago.
|
Energija izstrelka
|
08-01-2017, 13:19
(Ta prispevek je bil nazadnje popravljen: 08-01-2017, 13:25 od Robert91922.)
hitrost x hitrost (v m/s) x masa (v gramih) / 2000 = E (v Joul-ih)
Better be judged by twelve than carried by six
Gun Control is the comforting lies that people tell themselves in order to deal with media induced hoplophobia.
08-01-2017, 13:25
Razlaga bolj po domače za 9x19
Krogla 124grs = 8g Vo = 370m/s 0.008kg x 370m/s x 370m/s :2 = 547 J
08-01-2017, 13:31
Torej npr. za 124 gr Los, če je dosežen minimalni IPSC faktor 125 je energija v joulih 379,98. Ali imam prav.
08-01-2017, 15:02
124 gr = 8,04 g, Fak 125 = m(gr) × V (fps) × 10E-3 -> V fps = 125 / m(gr) × 10E3 = 1008 fps -> [0,305 m/s = 1 fps] -> 307,4 m/s -> E kin = m × V^2 / 2 = 0,008 × 307,4^2 / 2 = 378 J
Prav imaš!
V (m/s) = V (fps) × 0,305
m (grain) = m (gram) × 15,432 FAK = m (grain) × V (fps) / 1000 E (kin) = m (gram) × V (m/s)^2 / 2000 ->E kin = (m (grain) / 15,432) × ((FAK × 1000 / m (grain) × 0,305)^2 /2000 ==> E kin = FAK^2 / m (grain) × 3 [= 3 × FAK × FAK / m (grain)] |
|
|
Uporabnikov, ki berejo to temo: 1 Gost(ov)